## Range Partitioning Sort

#### Assumptions:

Assume n
processors, P

_{0}, P_{1}, …, P_{n-1}and n disks D_{0}, D_{1}, …, D_{n-1}.
Disk D

_{i}is associated with Processor P_{i}.
Relation R is partitioned into R

_{0}, R_{1}, …, R_{n-1}using Round-robin technique or Hash Partitioning technique or Range Partitioning technique (if range partitioned on some other attribute other than sorting attribute)#### Objective:

Our objective
is to sort a relation (table) R

_{i}that resides on n disks on an attribute A in parallel.#### Steps:

*Partition the relations R*

**Step 1:**_{i }on the sorting attribute A at every processor using a range vector

**v**. Send the partitioned records which fall in the i

^{th}range to Processor P

_{i}where they are temporarily stored in D

_{i}.

*Sort each partition locally at each processor P*

**Step 2:**_{i}. And, send the sorted results for merging with all the other sorted results which is trivial process.

#### Point to note:

Range
partition must be done using a good range-partitioning vector. Otherwise, skew
might be the problem.

#### Example:

Let us explain
the above said process with simple example.Consider the
following relation schema Employee;

**Employee (Emp_ID, EName, Salary)**

Assume that
relation

**into 3 disks D***Employee is permanently partitioned using Round-robin technique*_{0}, D_{1}, and D_{2}which are associated with processors P_{0}, P_{1}, and P_{2}. At processors P_{0}, P_{1}, and P_{2}, the relations are named Employee0, Employee1 and Employee2 respectively. This initial state is given in Figure 1.Figure 1 |

Assume that
the following sorting query is initiated.

**SELECT * FROM Employee ORDER BY Salary;**

As already
said, the table Employee is not partitioned on the sorting attribute Salary. Then,
the Range-Partitioning technique works as follows;

**Step 1:**

At first we
have to identify a range vector v on the Salary attribute. The range vector is
of the form

**v[v0, v1, …, vn-2]**. For our example, let us assume the following range vector;**v[14000, 24000]**

This range
vector represents 3 ranges, range 0 (14000 and less), range 1 (14001 to 24000)
and range 2 (24001 and more).

Redistribute the
relations Employee0, Employee1 and Employee2 using these range vectors into 3
disks temporarily. After this distribution disk 0 will have range 0 records (i.e,
records with salary value less than or equal to 14000), disk 1 will have range
1 records (i.e, records with salary value greater than 14000 and less than or
equal to 24000), and disk 2 will have range 2 records (i.e, records with salary
value greater than 24000).

This redistribution
according to range vector v is represented in Figure 2 as links to all the
disks from all the relations. Temp_Employee0, Temp_Employee1, and Temp_Employee2,
are the relations after successful redistribution. These tables are stored temporarily
in disks D

_{0}, D_{1}, and D_{2}. (They can also be stored in Main memories (M_{0}, M_{1}, M_{2}) if they fit into RAM).Figure 2 |

**Step 2:**

Now, we got temporary
relations at all the disks after redistribution.

At this
point, all the processors sort the data assigned to them in ascending order of
Salary individually. The process of performing the same operation in parallel
on different sets of data is called

**.***Data Parallelism*
Final Result:

After the processors
completed the sorting, we can simply collect the data from different processors
and merge them. This merge process is straightforward as we have data already
sorted for every range. Hence, collecting sorted records from partition 0, partition
1 and partition 2 and merging them will give us final sorted output.

## No comments:

## Post a comment