tag:blogger.com,1999:blog-7628532110401488083.post907455939663685703..comments2024-03-28T13:44:16.926+05:30Comments on Computer Science and Engineering - Tutorials, Notes, MCQs, Questions and Answers: Normalization Solved Exercise Set 3Saravanakumar Kandasamyhttp://www.blogger.com/profile/16961761432041628004noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-7628532110401488083.post-3578228808199597712020-11-28T10:13:16.140+05:302020-11-28T10:13:16.140+05:30Hi Sherman, CD is a super key because we found tha...Hi Sherman, CD is a super key because we found that C is a key. CD is not a candidate key. <br />Candidate key is a minimal super key for which no proper subset is a key. Proper subset for CD is {C} and {D}. But already C is a key. Hence, CD cannot be a key (candidate).K Saravanakumar Vellore Institute of Technologyhttps://www.blogger.com/profile/10369600808706860889noreply@blogger.comtag:blogger.com,1999:blog-7628532110401488083.post-79502728938888343822020-11-28T04:46:20.995+05:302020-11-28T04:46:20.995+05:30Hello Admin, Why can't CD be a key as well? W...Hello Admin, Why can't CD be a key as well? We know that , with reflexivity rule, CD -> E: CDE, and with C ->AD, and D->B. Isn't CD be a key?Shermanhttps://www.blogger.com/profile/01242843893891036870noreply@blogger.com